\(\left({\sqrt{3}-\frac{1}{\sqrt{3}}}\right)^{2}\) simplifies to :
\((\sqrt{3}-\frac{1}{\sqrt{3}})^{2} = (\sqrt{3})^{2}+(\frac{1}{\sqrt{3}})^{2}-2\times\sqrt{3}\times\frac{1}{\sqrt{3}}\)
\(= 3+\frac{1}{3}-2\)
\(= 1+\frac{1}{3}\)
\(= \frac{4}{3}\)
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