$$\left\{ {\left( {\sqrt {72} - \sqrt {18} } \right) \div \sqrt {12} } \right\}$

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Question

$$\left\{ {\left( {\sqrt {72} - \sqrt {18} } \right) \div \sqrt {12} } \right\}$$ is equal to = ?

Options:

A . $$\sqrt 6 $$

B . $$\frac{{\sqrt 3 }}{2}$$

C . $$\frac{{\sqrt 2 }}{3}$$

D . $$\frac{{\sqrt 6 }}{2}$$

Answer: Option D
$$\eqalign{
& {\text{According to the question,}} \cr
& \frac{{\sqrt {72} - \sqrt {18} }}{{\sqrt {12} }} \cr
& \Rightarrow \sqrt {\frac{{72}}{{12}}} - \sqrt {\frac{{18}}{{12}}} \cr
& \Rightarrow \sqrt 6 - \sqrt {\frac{6}{4}} \cr
& \Rightarrow \frac{{\sqrt 6 }}{2} \cr} $$

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