In two triangles , the ratio of the areas is 4 : 3 and he ratio of their height is 3 : 4 . Find the ratio of their bases.
Let the bases of the two triangles be `x` and y and their height be 3 h and 4h respectively Then ,
`(1/2 xx x xx 3h)/(1/2 xx y xx 4y) = 4/3`
`hArr x/y = (4/3 xx 4/3)`
`hArr x/y = 16/9`
`:.` Required ratio = 16 : 9 .
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