Question
In the league tournament with the conditions as described in the first question, a bookie Charlie follows the following system. In a match between two teams "a” and "b”, the team "a” wins more of their previous matches. If team "a” wins this match, he will pay Rs. 1.5 for every Re. 1 bet on team "a”. If team "b” wins this match, he will pay Rs. 2 for every Re. 1 bet on team "b”. In every match, equal money was bet on both the teams playing in that match. What was Charlie's gain, as a fraction, on the total money that he bet?
Answer: Option C
:
C
Based on the information in the previous question, Charlie gets, say Rs 1 each from the betters of the two teams. In 6 matches, Charlie gets Rs 12. We know that the better team is winning in each case; hence his net gain is 50 paise in 6 matches ⇒ his total gain =(0.5×6)12=14
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:
C
Based on the information in the previous question, Charlie gets, say Rs 1 each from the betters of the two teams. In 6 matches, Charlie gets Rs 12. We know that the better team is winning in each case; hence his net gain is 50 paise in 6 matches ⇒ his total gain =(0.5×6)12=14
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