D ≥ N -- (i) N = V -- (ii) W ≤ V -- (iii)combining (i) and (ii), we get:D ≥ N = V => D ≥ N. Hence, conclusion III (V = D) is not necessary true.Again, combining all (i), (ii) and (iii), we getD ≥ N = V ≥ W => D ≥ W. Hence, neither conclusion I (D = W) or conclusion II (W < D) is true. But both conclusion I (D = W) and conclusion II (W
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