H < B -- (i) M ≥ B -- (ii) K + M -- (iii)combining (ii) and (iii), we get:K = M ≥ B => K ≥ B. Hence, neither conclusion II (B = K) or conclusion III (K > B) is true. But, both conclusion I and II together make a complementary pair. Hence, either conclusion II (B = K) or conclusion III (K > B) is true.Again combining all (i), (ii) and (iii) we get K = M ≥ B > H => K > H (conclusion I). Hence conclusion I (K > H) is true.
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