M > R --- (i) R ≥ K --- (ii) J < K --- (iii)combining (i), (ii) and (iii), we get:M > R ≥ K > J => M > J (conclusion I),R > J (conclusion II),M > K (conclusion III),Hence, conclusion I (M > J), conclusion II (J < R) and conclusion III (K < M) are all true.
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