In measuring the sides of a rectangle , one side is taken 5% in excess, and the other 4% in deficit. . Find the error percent in the area calculated from these measurements.
Let `x` and y be the side of the rectangle , Then correct area = `xy`
Calculated area = `(105/100 x) xx (96/100 y) = 504/500 xy`
Error in measurement =` (504/500 xy) - xy = 4/500 xy`
`:.` Error % = `[ 4/500 xy xx (1)/(xy) xx 100]%` = `4/5`% = 0.8%
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