In an interference pattern 16th order maximum corresponds to 600nm .

Question

In an interference pattern

16^{t h}

order maximum corresponds to 600nm . What order will be visible if 480nm is used in the same position:

Options:

A . 5

B . 10

C . 15

D . 20

Answer: Option D
:
D

n = 16, y = \frac{n λ D}{d} = \frac{n^{'} λ^{'} D}{d}

n λ = n^{'} λ^{'}

\Rightarrow 16 \times 600 = n^{'} \times 480

\Rightarrow n^{'} = 20

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