In an examination, a student had to obtain 33% of the maximum marks to pass. He

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In an examination, a student had to obtain 33% of the maximum marks to pass. He got 125 marks and failed by 40 marks. The maximum marks were

Options:

A . 800

B . 600

C . 1000

D . 500

Answer: Option D
Answer: (d)
Let the maximum marks be x.
${x × 33}/100 = 125 + 40 = 165$
x = ${165 × 100}/33 =500$
Using Rule 24,
a = 33%, b = 125, c = 40
Maximum marks = ${(b + c)}/a × 100$
= ${(125 + 40)}/33 × 100$
= ${165 × 100}/35 = 500$

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