In an examination, 34% of the students failed in mathematics and 42% failed in English . If 20% of the students failed in both the subjects , then the percentage of students who passed in both the subjects was :
n(A) = 34, n(B) = 42, n`(A nn B)` = 20.
So, n`(A uu B)= n(A) + n(B) - n(A nn B)` = 34 + 42 - 20 = 56.
`:.` percentage failed in either or both the subjects = 56.
Hence,percentage passed = (100 - 56)% = 44%
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