Answer: Option A
Answer: (a)
Let total number of students = 100
Number of failures in Maths = 34
Number of failures in English = 42
Number of failures in both subjects = 20
Number of failures in Maths or English or both
= 34 + 42 – 20 = 56
Number of students who passed in both subjects
= 100 – 56 = 44
The required percentage = 44%
Using Rule 23,
a = 34%, b = 42%, c = 20%
Passed candidates in both the subjects
= 100 – (a + b – c)
= 100 – (34 + 42 – 20) = 100 – 56 = 44%