Question
In an electromagnetic wave, the amplitude of electric field is 1 V/m. the frequency of wave is 5× 1014Hz. The wave is propagating along z-axis. The average energy density of electric field, in Joulem3, will be
Answer: Option B
:
B
Average energy density of electric field is given by
ue=12ϵ0E2=12ϵ0(E0√2)2=14ϵ0E20
=14×8.85×10−12(1)2=2.2×10−12J/m3.
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B
Average energy density of electric field is given by
ue=12ϵ0E2=12ϵ0(E0√2)2=14ϵ0E20
=14×8.85×10−12(1)2=2.2×10−12J/m3.
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