In a certain perfume mixture consisting of only two flavors, for every 3 milliliters of Flavour A, there are 7 milliliters of Flavour B. After 10 milliliters of Flavour C are added to this perfume mixture, what is the ratio of the quantities of Flavour A to Flavour C? 1. Before flavour C was added, there were 50 milliliters of perfume mixture. 2. After flavour C was added, there were 60 milliliters of perfume mixture.
Options:
A .
A
B .
B
C .
C
D .
D
Answer: Option B : B The question stem already tells us that there are 10 milliliters of Flavour C in the final perfume mixture. We also know that the original perfume mixture consists of only Flavours A and B in the ratio of 3 to 7. Thus, we need the original volume of the perfume mixture to determine the amount of FlavourA contained in it. SUFFICIENT: This tells us that original perfume mixture was 50 milliliters. Thus, there must have been 15 milliliters of Flavour A (to 35 milliliters of Flavour B). Theratio of A to C is 15 to 10 (or 3 to 2). SUFFICIENT: This tells us that the final perfume mixture was 60 milliliters. We know that this includes 10 milliliters of Flavour C. This means the original perfume mixture contained 50 milliliters. Thus, there must have been 15 milliliters of Flavour A (to 35 milliliter of Flavour B). The ratio of A to C is 15 to 10 (or 3 to 2).
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