Sail E0 Webinar
Question
If xdydx=y(log ylog x+1), then the solution of the equation is
Options:
A .  y log(xy)=cx
B .  x log(yx)=cy
C .  log(yx)=cx
D .  log(xy)=cx
Answer: Option C
:
C
dydx=yx(logyx+1)
Put y=vxdydx=v+xdvdx
v+xdvdx=vlogv+v1vlogvdv=1xdx1vlogvdv=1xdxlog(logv)=logx+logc
logyx=cx

Was this answer helpful ?
Next Question

Submit Solution

Your email address will not be published. Required fields are marked *

Latest Videos

Latest Test Papers