Question
If xcos y+ycos x=5. Then
Answer: Option C
:
C
xcosy+ycosx=5
⇒ecosylogex+ecosxlogey=5
∴ecosylogex{cosyx−logex(siny)dydx}+ecosxlogey{cosxydydx−sinxlogey}=0
Putx=y=1,(cos1−0)+(cos1dydx−0)=0
∴dydx=−1
ory′=−1
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:
C
xcosy+ycosx=5
⇒ecosylogex+ecosxlogey=5
∴ecosylogex{cosyx−logex(siny)dydx}+ecosxlogey{cosxydydx−sinxlogey}=0
Putx=y=1,(cos1−0)+(cos1dydx−0)=0
∴dydx=−1
ory′=−1
Was this answer helpful ?
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