If (x - 3)2 + (y - 5)2 + (z - 4)2 = 0, then the value of $$\frac{{{x^2}}}{9}{\te

Question

If (x - 3)2 + (y - 5)2 + (z - 4)2 = 0, then the value of $$\frac{{{x^2}}}{9}{\text{ + }}\frac{{{y^2}}}{{25}}{\text{ + }}\frac{{{z^2}}}{{16}}$$ is?

Options:

A . 12

B . 9

C . 3

D . 1

Answer: Option C

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