Answer: Option C $$\eqalign{
& {A_1} = {x^2}{\text{ and }}{A_2} = {\left( {2x} \right)^2} = 4{x^2} \cr
& {\text{Increase in area}} = \left( {4{x^2} - {x^2}} \right) \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 3{x^2} \cr
& {\text{Increase % }} = \left( {\frac{{3{x^2}}}{{{x^2}}} \times 100} \right)\% \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 300\% \cr} $$
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