If the radius of a sphere is doubled, how many times does its volume becomes ?
Options:
A . 2 times
B . 4 times
C . 6 times
D . 8 times
Answer: Option D Let the original radius be r Then, original volume = $$\frac{4}{3}\pi {r^3}$$ New area = 2r ∴ New volume : $$\eqalign{ & = \frac{4}{3}\pi {\left( {2r} \right)^3} \cr & = 8 \times \frac{4}{3}\pi {r^3} \cr & = 8 \times {\text{Original volume}} \cr} $$
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