If the radius of a circle is decreased by 50% , find the percentage decrease in its area.
Let original radius = R, New radius = `50/100 R = R/2`
Original area = `pi R^2` and New area = `pi (R/2)^2` = ` (pi R^2)/(4)`
`:.` decrease in area = `((3 pi R^2)/(4) xx (1)/(pi R^2) xx 100)`% = 75%
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