If the population of a town is 64000 and its annual increase is 10%, then its co

Question

If the population of a town is 64000 and its annual increase is 10%, then its correct population at the end of 3 years will be :

Options:

A . 85184

B . 80000

C . 85000

D . 85100

Answer: Option A
Answer: (a)
Using Rule 17,
Population of town = $P(1 + R/100)^T$
= $64000(1 + 10/100)^3$
= $64000 × 11/10 × 11/10 × 11/10$ = 85184

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