If the perimeters of a square and a rectangle are the same , then the area A and B enclosed by hem would satisfy the condition :
Take a square of side 4 cm and a rectangle having l = 6 cm. , b = 2 cm.
Then , perimeter of square = perimeter of rectangle.
Area of square = 16 `cm^2` , area of rectangle = 12 `cm^2`
`:.` A > B.
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