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If the length of a copper wire is increased by 5% due to stretching. What will be the percentage increase in its resistance? 


Options:
A .   12%
B .   11.5%
C .   20.25%
D .   10.25%
Answer: Option D
:
D
Resistance, R=ρLA
where:
ρ: Resistivity,
L: Length of the wire
A:  Cross-sectional area of the wire.
The length of the copper wire is increased by 5%.
So, new length is:
L=L+5100L=1.05L
Let the new cross-sectional area be A.
On stretching the wire, its volume will remain constant.
LA=LA
A=A1.05
New resistance will become:
R=ρLA
R=ρ(1.05LA/1.05)
R=1.052R=1.1025R
Percentage increase in its resistance is,
p=RRR×100
p=(1.10251)RR×100
p=10.25 %

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