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If the difference between the length and breadth of a rectangle is 23 m and its perimeter is 206 m, what is its area?
Options:
A .  2800 m2
B .  2740 m2
C .  2520 m2
D .  2200 m2
Answer: Option C

Answer : Option C

Explanation :

l - b = 23 ...................(Equation 1)
perimeter = 2(l + b) = 206
=> l + b = 103.............(Equation 2)
(Equation 1) + (Equation 2) => 2l = 23 + 103 = 126
=> l = 126/2 = 63 metre
Substituting this value of l in (Equation 1), we get
63 - b = 23
=> b = 63 - 23 = 40 metre
Area = lb = 63 × 40 = 2520 m2



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