If the area of the trapezium whose parallel sides are 6 cm and 10 cm is 32 sq. cm, then the distance between the parallel sides is :
Options:
A . 2 cm
B . 4 cm
C . 5 cm
D . 8 cm
Answer: Option B Let the required distance be x cm Then, $$\eqalign{ & \Rightarrow \frac{1}{2} \times \left( {6 + 10} \right) \times x = 32 \cr & \Rightarrow x = 4\,cm \cr} $$
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