If $${\text{tan }}{9^ \circ } = \frac{p}{q}{\text{,}}$$ then the value of $$\

Question

If $${\text{tan }}{9^ \circ } = \frac{p}{q}{\text{,}}$$ then the value of $$\frac{{{\text{se}}{{\text{c}}^2}{\text{8}}{{\text{1}}^ \circ }}}{{1 + {{\cot }^2}{{81}^ \circ }}}$$ is?

Options:

A . $$\frac{p}{q}$$

B . 1

C . $$\frac{{{p^2}}}{{{q^2}}}$$

D . $$\frac{{{q^2}}}{{{p^2}}}$$

Answer: Option D

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