If $${\text{2cos}}\theta - \sin \theta = \frac{1}{{\sqrt 2 }},$$ $$\left( {{0^ \circ } Options: A . &nbsp$$\frac{1}{{\sqrt 2 }}$$ B . &nbsp$$\sqrt 2 $$ C . &nbsp$$\frac{3}{{\sqrt 2 }}$$ D . &nbsp$$\frac{1}{{\sqrt 3 }}$$

If $${\text{2cos}}\theta - \sin \theta = \frac{1}{{\sqrt 2 }},$$ $$\left( {

Question

If $${\text{2cos}}\theta - \sin \theta = \frac{1}{{\sqrt 2 }},$$ $$\left( {{0^ \circ } < \theta < {{90}^ \circ }} \right)$$ the value of $$2\sin \theta $$ + $$\cos \theta $$ is?

Options:

A . $$\frac{1}{{\sqrt 2 }}$$

B . $$\sqrt 2 $$

C . $$\frac{3}{{\sqrt 2 }}$$

D . $$\frac{1}{{\sqrt 3 }}$$

Answer: Option C

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