If n is a natural number and n = $${p_1}^{{x_1}}$$ $${p_2}^{{x_2}}$$ $${p_3}^{{x_3}}$$ where p1, p2, p3 are distinct prime factors, then the number of prime factors for n is : Options: A . &nbsp$${x_1} + {x_2} + {x_3}$$ B . &nbsp$${x_1} \times {x_2} \times {x_3}$$ C . &nbsp$$\left( {{x_1} + 1} \right)\left( {{x_2} + 1} \right)\left( {{x_3} + 1} \right)$$ D . &nbspNone of these

If n is a natural number and n = $${p_1}^{{x_1}}$$ $${p_2}^{{x_2}}$$ $${p

Question

If n is a natural number and n = $${p_1}^{{x_1}}$$ $${p_2}^{{x_2}}$$ $${p_3}^{{x_3}}$$ where p1, p2, p3 are distinct prime factors, then the number of prime factors for n is :

Options:

A . $${x_1} + {x_2} + {x_3}$$

B . $${x_1} \times {x_2} \times {x_3}$$

C . $$\left( {{x_1} + 1} \right)\left( {{x_2} + 1} \right)\left( {{x_3} + 1} \right)$$

D . None of these

Answer: Option B

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