If $${\log _x}\left( {\frac{9}{{16}}} \right) =

Question

If $${\log _x}\left( {\frac{9}{{16}}} \right) = - \frac{1}{2},$$ then x is equal to:

Options:

A . $$ - \frac{3}{4}$$

B . $$\frac{3}{4}$$

C . $$\frac{{81}}{{256}}$$

D . $$\frac{{256}}{{81}}$$

Answer: Option D

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