If in a ΔABC, cosAa=cosBb=cosCc, then what can be said about the triangle?
Options:
A .  Isoceles triangle
B .  Right angled triangle
C .  Equilateral triangle
D .  Acute triangle
E .  1
Answer: Option C : C Since rule says that = asinA=bsinB=csinC=k Therefore,a=k(sinA), b=k(sinB) and c=k(sinC) We can write cosAa=cosBb=cosCc as cosAksinA=cosBksinB=cosCksinC =cot A=cot B=cot C ⇒ A=B=C(Equilateral Triangle).
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