If $$\frac{1}{{x + 2}},$$ $$\frac{1}{{x + 3}},$$ $$\frac{1}{{x + 5}}$$ are in A.P. then x = ? Options: A . &nbsp5 B . &nbsp3 C . &nbsp1 D . &nbsp2

If $$\frac{1}{{x + 2}},$$ $$\frac{1}{{x + 3}},$$ $$\frac{1}{{x + 5}}$$ ar

Question

If $$\frac{1}{{x + 2}},$$ $$\frac{1}{{x + 3}},$$ $$\frac{1}{{x + 5}}$$ are in A.P. then x = ?

Options:

A . 5

B . 3

C . 1

D . 2

Answer: Option C

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