Answer: Option D $$\eqalign{
& {{\text{A}}_{\text{1}}} = \frac{{\sqrt 3 }}{2}{a^2}{\text{ and }} \cr
& {{\text{A}}_{\text{2}}} = \frac{{\sqrt 3 }}{2}{\left( {2a} \right)^2} \cr
& \,\,\,\,\,\,\,\,\,\, = 4 \times \frac{{\sqrt 3 }}{2}{a^2} \cr
& \,\,\,\,\,\,\,\,\,\, = 4{{\text{A}}_{\text{1}}} \cr
& \therefore {\text{K}} = 4 \cr} $$
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