Question
If a circle whose centre is (1, –3) touches the line 3x – 4y –5 = 0, then the radius of the circle is
Answer: Option A
:
A
Radius = perpendicular distance from (1, -3) to the given line 3x - 4y - 5 = 0.
i.e. ∣∣∣3+12−5√52∣∣∣=2.
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:
A
Radius = perpendicular distance from (1, -3) to the given line 3x - 4y - 5 = 0.
i.e. ∣∣∣3+12−5√52∣∣∣=2.
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