If a, b, c, all distinct are such that a,b, and c are in AP and b-a, c-b, and a are in GP then a:b:c =?
Options:
A .  2:3:4
B .  1:2:4
C .  1:2:3
D .  4:6:7
E .  None of the above
Answer: Option C : C Going from answer options is the best choice. **Observe that only options (a) and (c) are in an AP. By Assumption technique; taking a=2, b=3 and c=4 b-a=1,c-b=1 and a=2, which does not form a GP. Hence this option can never be true Taking a=1, b=2 and c=3. b-a=1, c-b=1 and a=1 is in a GP. Hence, answer option (c) is the right one
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