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If a and b are two distinct natural numbers, which one of the following is true ?
Options:
A .  $$\sqrt {a + b} > \sqrt a + \sqrt b $$
B .  $$\sqrt {a + b} = \sqrt a + \sqrt b $$
C .  $$\sqrt {a + b} < \sqrt a + \sqrt b $$
D .  $$ab = 1$$
Answer: Option C
$$\eqalign{
& \sqrt {a + b\,} \,{\text{and }}\sqrt a + \sqrt b \cr
& {\text{Squaring both sides}} \cr
& {(\sqrt {a + b\,} )^2}{\text{and (}}\sqrt a + \sqrt b {)^2} \cr
& \Rightarrow a + b\,\,{\text{and}}\,a + b + 2\sqrt a \sqrt b \cr
& So\,\sqrt {a + b\,} \, < {\text{ }}\sqrt a + \sqrt b \cr} $$

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