Answer: Option C
:
C
'abc' has exactly 3 factors, so 'abc' should be square of prime number.
Let the square root of 'abc' be 'p' (where 'p' is prime).
'abcabc'= abc$\times$ 1001 = $p^2\times 13\times 11\times 7$
If 'p' is any prime number other than 13, 11 or 7, then no. of factors = 3 x 2 x 2 x 2 = 24 (no. will be of the form$p^2\times 13\times 11\times 7$)
If 'p' is any prime number among 13, 11 or 7, then no. of factors = 4 x 2 x 2 = 16 (no. will be of the form$7^3\times 13\times 11,ifp=7$)
$\therefore$ No. of factors can be 16 or 24.