if `(5 + 2sqrt(3))/(7 + 4sqrt(3))` =` a + bsqrt(3)` , them :
`a + bsqrt(3)` = `(5 + 2sqrt(3))/(7 + 4sqrt(3))` x `(7 - 4sqrt(3))/(7 - 4sqrt(3))`
`(35 - 20sqrt(3) + 14sqrt(3) - 24)/((7)^2 - (4sqrt(3))^2)` = `(11 - 6sqrt(3))/(49 - 48)` = `11 - 6sqrt(3)`
`:.` a = 11, b = - 6
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