**If 4800 vehicles were sold in Delhi, what was the total number of vehicles sold in Chennai?**

__Question:__**Options:**

A. | 4800 | |

B. | 2400 | |

C. | 5100 | |

D. | None of these |

**Answer: Option A**

: A

Number of Auto Rickshaws sold in Delhi =24100 × 4800 = 1152, Which is 24% of total number of Auto Rickshaws sold in the given cities.

So, total number of Auto Rickshaws = 4800.

Number of Auto Rickshaws sold in Chennai = 10100 × 4800 = 480, which is 10% of total number of vehicles sold inChennai.

The total number of vehicles sold in Chennai = 4800

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## More Questions on This Topic :

- 24,000
- 36,000
- 18,000
- 48,000

**Answer: Option B**

: B

Let the amount invested by Gopal and Ram be 2x and 3x respectively. Gopal further invested Rs 2 lakh. Given (2x + 2) = 3x or x = 2 lakh. Hence, initial amount paid by Gopal and Ram to Krishna is 4 lakh and 6 lakh respectively. Hence, total money invested by them together = (6 + 6) = 12 lakh. The total revenue generated = 12 × 25% = 3 lakh. The ratio of revenue from coconut and lemon trees are in the ratio 3 : 2. Hence, revenue from coconut = Rs 1,80,000 and revenue from lemons = Rs 1,20,000. So, total output of coconut = (1,80,0005) =36,000.

__Question 3.__**In the previous question, if in 1994 prices increased by 5%, 1% and 10% while the volume of sales break-up was 40%, 30% and 30% for plywood, saw timber and logs respectively, then want was the average realization?**

- 18.95
- 16.45
- 13.15
- 10.25

**Answer: Option C**

: C

The change for price increase = [(4×5.26×1.05)+(3×14.28×1.01)+(3×20×1.1)](4+2+3) = Rs 13.15

**If the final amount of money that Akash had with him was Rs. 100, what was the initial amount he held with him?**

__Question 4.__- 120
- 8
- 4
- 96

**Answer: Option D**

: D

At the end of Round IV, Akash's earnings = -8 (Round I) + 20 (Round II) + 0 (Round III) -8 (Round IV) = Rs. 4 If total = Rs. 100, then the initial amount with Akash = Rs. 100 - Rs. 4 = Rs. 96.

: From the given condition "if any person had predicted that a single horse would win each of the eight games, he would not have gained or lost any amount". It means, every horse won 2 races.

From the given condition "B received the maximum amount of 16000". Let B predicted x races and y races incorrect.

3000 x-1000 y=16000 ...................(1) And x+y=8......................... (2)

From equation (1) and (2), we can determine x=6 and y=2

From the second condition "Had C made one more correct prediction and B made one more incorrect prediction.

The amounts gained by them at the end of the races would have interchanged". We can conclude C predicted 5

races correct and 3 races incorrect. And E neither gained nor lost any amount. So, E predicted 2 races correct and 6

races incorrect.

PersonsWinLoseScoreB6216,000C5312,000E260

Now, from the given table, we can easily conclude below table :-

R1R2R3R4R5R6R7R8CheetahBingoAzureBingo

Because B's 6 predictions are correct. Out of 8 predictions, 4 times B predicted "Dylan". And we know Dylan won only two times. It means B's predictions for Race R2,R4,R5 and R8 were correct.

R1R2R3R4R5R6R7R8AzureCheetahDylanBingoAzureCheetahDylanBingox(B,C)(A,B,C,D)(A,B,D,E)(A,B,C)(A,C,D)(B,C,D)(B,E)

Now, we can conclude below table. Because, E's 2 predictions were correct and Cheetah won 2 times. So, cheetah

has to win Race R5. C's 5 predictions were incorrect. So, C cannot be winner of race R1

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