Question
If $$13 = \frac{{13w}}{{\left( {1 - w} \right)}}$$ , then (2w)2 = ?
Answer: Option C $$\eqalign{
& \Rightarrow \frac{{13}}{1} = \frac{{13w}}{{\left( {1 - w} \right)}} \cr
& \Rightarrow \frac{w}{{\left( {1 - w} \right)}} = 1 \cr
& \Rightarrow w = 1 - w \cr
& \Rightarrow 2w = 1 \cr
& \Rightarrow w = \frac{1}{2} \cr
& \therefore {\left( {2w} \right)^2} \cr
& = 4{w^2} \cr
& = 4 \times \frac{1}{4} \cr
& = 1 \cr} $$
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