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Question
I. x2 - x - 42 = 0, II. y2 - 17y + 72 = 0 to solve both the equations to find the values of x and y?
Options:
A .  If x < y
B .  If x > y
C .  If x ≤ y
D .  If x ≥ y
E .  If x = y or the relationship between x and y cannot be established.
Answer: Option A


I. x2 - 7x + 6x - 42 = 0
=> (x - 7)(x + 6) = 0 => x = 7, -6
II. y2 - 8y - 9y + 72 = 0
=> (y - 8)(y - 9) = 0 => y = 8, 9
=> x < y



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