Question
How much pure alcohol has to be added to 400 ml of a solution containing 15% of alcohol to change the concentration of alcohol in the mixture to 32% ?
Answer: Option C Answer: (c)Alcohol = $(15/100 × 400)$ml = 60 ml.Water = 340 ml. Let x ml of alcohol be added. Then, ${60 + x}/{400 + x} × 100 = 32$ or ${60 + x}/{400 + x} = 32/100 = 8/25$or 1500 + 25x = 3200 + 8x or 17x = 1700 or x = 100 ml
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