Answer: Option B
Let the length of each edge of small cube be a1 and that of larger cube be a2
Then,
$$\eqalign{
& 6a_1^2 = 96\, \cr
& \Rightarrow a_1^2 = 16 \cr
& \Rightarrow {a_1} = 4\,and \cr
& 6a_2^2 = 384 \cr
& \Rightarrow a_2^2 = 64 \cr
& \Rightarrow {a_2} = 8 \cr} $$
∴ Number of cubes formed :
$$\eqalign{
& = \frac{{{\text{Volume of larger cube}}}}{{{\text{Volume of smaller cube}}}} \cr
& = \left( {\frac{{8 \times 8 \times 8}}{{4 \times 4 \times 4}}} \right) \cr
& = 8 \cr} $$