Question: How many of the given the pipeline segments are carrying less than 20% of their capacity___
Options:
:
As the pipeline AB is working at its full capacity it must be transferring 2500 litres of oil. Out of which 1200 litres is taken by B, 700 litres is taken by C, and 400 litres oil taken by E. Remaining 200 litres will go to D but D's requirement is 700 litres so AD must be carrying 500 litres.
20% of 2500 is 500. By observing the figure, the pipes where the flow is less than 500 are CE and CD i.e., 2 pipes.
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Question 1. If the difference between the capacity of a pipeline and the amount of oil flowing in it is called as the slack in that pipeline, what is the slack in the pipeline connecting units C and D (in litres)?___
:
As the pipeline AB is working at its full capacity it must be transferring 2500 litres of oil. Out of which 1200 litres is taken by B, 700 litres is taken by C, and 400 litres oil taken by E. Remaining 200 litres will go to D but D's requirement is 700 litres so AD must be carrying 500 litres.
Again from the figure, the slack in the pipeline connecting C and D is 2300 litres.
Question 2. If N is a positive odd integer, what is the average of a certain set of N integers?
(1) The integers in the set are consecutive multiples of 3
(2) The median of the set of integers is 33
(1) The integers in the set are consecutive multiples of 3
(2) The median of the set of integers is 33
- If the question can be answered with statement 1 alone
- If the question can be answered with statement 2 alone
- If both statement 1 and statement 2 are needed to answer the question and
- If the question cannot be answered even with the help of both statements
Answer: Option C
: C
(1) Insufficient. There is no way to find out the mean using this. Consider one set {3, 6, 9} and another {6, 9, 12}.
(2) Insufficient. Knowing that there is an odd number of terms in the set and that the median is 33 does not tell us what the mean is. (1&2) Sufficient. In an ordered set with an odd number of terms, the median is equal to the "middle" term. Moreover, in an equally distributed set of integers (in this case, consecutive multiples of 3) the median will be equal to the mean itself.
: C
(1) Insufficient. There is no way to find out the mean using this. Consider one set {3, 6, 9} and another {6, 9, 12}.
(2) Insufficient. Knowing that there is an odd number of terms in the set and that the median is 33 does not tell us what the mean is. (1&2) Sufficient. In an ordered set with an odd number of terms, the median is equal to the "middle" term. Moreover, in an equally distributed set of integers (in this case, consecutive multiples of 3) the median will be equal to the mean itself.
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