How many different Arithmetic Progressions can you form with atleast three terms with first term 2 and last term 999?
Options:
A .  1
B .  3
C .  5
D .  6
E .  None of these
Answer: Option A : A Option e The number of AP’s= (Number offactors of 997 - 1), which is prime. Hence only one AP’s of998 terms can be formed. Answer is option a
Submit Comment/FeedBack