Question
How many correct predictions were made by D?___
Answer:
:
From the given condition "if any person had predicted that a single horse would win each of the eight games, he would not have gained or lost any amount". It means, every horse won 2 races.
From the given condition "B received the maximum amount of 16000". Let B predicted x races and y races incorrect.
3000 x-1000 y=16000 ...................(1) And x+y=8......................... (2)
From equation (1) and (2), we can determine x=6 and y=2
From the second condition "Had C made one more correct prediction and B made one more incorrect prediction.
The amounts gained by them at the end of the races would have interchanged". We can conclude C predicted 5
races correct and 3 races incorrect. And E neither gained nor lost any amount. So, E predicted 2 races correct and 6
races incorrect.
PersonsWinLoseScoreB6216,000C5312,000E260
Now, from the given table, we can easily conclude below table :-
R1R2R3R4R5R6R7R8CheetahBingoAzureBingo
Because B's 6 predictions are correct. Out of 8 predictions, 4 times B predicted "Dylan". And we know Dylan won only two times. It means B's predictions for Race R2,R4,R5 and R8 were correct.
R1R2R3R4R5R6R7R8AzureCheetahDylanBingoAzureCheetahDylanBingox(B,C)(A,B,C,D)(A,B,D,E)(A,B,C)(A,C,D)(B,C,D)(B,E)
Now, we can conclude below table. Because, E's 2 predictions were correct and Cheetah won 2 times. So, cheetah
has to win Race R5. C's 5 predictions were incorrect. So, C cannot be winner of race R1
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:
From the given condition "if any person had predicted that a single horse would win each of the eight games, he would not have gained or lost any amount". It means, every horse won 2 races.
From the given condition "B received the maximum amount of 16000". Let B predicted x races and y races incorrect.
3000 x-1000 y=16000 ...................(1) And x+y=8......................... (2)
From equation (1) and (2), we can determine x=6 and y=2
From the second condition "Had C made one more correct prediction and B made one more incorrect prediction.
The amounts gained by them at the end of the races would have interchanged". We can conclude C predicted 5
races correct and 3 races incorrect. And E neither gained nor lost any amount. So, E predicted 2 races correct and 6
races incorrect.
PersonsWinLoseScoreB6216,000C5312,000E260
Now, from the given table, we can easily conclude below table :-
R1R2R3R4R5R6R7R8CheetahBingoAzureBingo
Because B's 6 predictions are correct. Out of 8 predictions, 4 times B predicted "Dylan". And we know Dylan won only two times. It means B's predictions for Race R2,R4,R5 and R8 were correct.
R1R2R3R4R5R6R7R8AzureCheetahDylanBingoAzureCheetahDylanBingox(B,C)(A,B,C,D)(A,B,D,E)(A,B,C)(A,C,D)(B,C,D)(B,E)
Now, we can conclude below table. Because, E's 2 predictions were correct and Cheetah won 2 times. So, cheetah
has to win Race R5. C's 5 predictions were incorrect. So, C cannot be winner of race R1
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