Four particles each of mass M, are located at the vertices of a square with side L. The gravitational potential due to this at the centre of the square is
Options:
A .  −√32GML
B .  −√64GML2
C .  Zero
D .  √32GML
Answer: Option A : A Potential due to a point mass M at a distance r is−GMr Potential at the centre due to single mass = −GML√2 Potentialat the centre due to all four masses =−4√2GML=−√32×GML
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