Question
For the given linear equation y−3x+1=0, what are the values of y if x=[3,−4,2]?
Answer: Option D
:
D
We have y−3x+1=0
For x=3
⇒y−3(3)+1=0
∴y=8
For x=−4
⇒y−3(−4)+1=0
∴y=−13
For x=2
⇒y−3(2)+1=0
∴y=5
Thus, the values of y ifx=[3,−4,2] are 8, -13 and 5 respectively.
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:
D
We have y−3x+1=0
For x=3
⇒y−3(3)+1=0
∴y=8
For x=−4
⇒y−3(−4)+1=0
∴y=−13
For x=2
⇒y−3(2)+1=0
∴y=5
Thus, the values of y ifx=[3,−4,2] are 8, -13 and 5 respectively.
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