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For the equation x8+6x75x43x2+2x5=0, determine the maximum number of real roots possible.
Options:
A .  4
B .  3
C .  8
D .  7
E .  Can’t be determined
Answer: Option A
:
A
f(x)=x8+6x75x43x2+2x5
Check the number of positive roots= no. of sign changes in f(x) = 3
Check the number of negative roots = no. of sign changes in f(-x)
f(x)=x86x75x43x22x5. No. of sign changes = 1
Now check for zero as a root.f(0)=50
So, maximum number of real roots = 3 + 1 = 4. Hence option (a)

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