Five resistors are connected in circuit as shown with a 3 V battery. Find the ammeter reading.
Options:
A .  
1 A
B .  
2 A
C .  
3 A
D .  
4 A
Answer: Option A : A Given, Resistance values, R1=R2=R3=3Ω R4=R5=0.5Ω Here the resistances R1 and R2 are in series. Let the equivalent resistance of this combination be R12. R12=R1+R2 R12=3+3=6Ω Now R12 and R3 are in parallel. Let the equivalent resistance of this combination be R123. ⟹1R123=1R12+1R3 1R123=16+13 R123=2Ω Now, R4,R123 and R5 are in series. Let the equivalent resistance of this combination be R. ⟹R=R4+R123+R5 R=0.5+2+0.5Ω R=3Ω Using Ohms law, I=VR I=3V3Ω=1A
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