Question
Find (0.4p−0.5q)2. If p = 5 and q = 4, evaluate the value of the expression. [3 MARKS]
Answer:
:
Steps: 1 Mark
Final expression: 1 Mark
Value: 1 Mark
(0.4p−0.5q)2
=(0.4p−0.5q)×(0.4p−0.5q)
=(0.4p)×(0.4p)−(0.4p×0.5q+0.4p×0.5q)+(0.5q)×(0.5q)
=0.16p2−0.40pq+0.25q2
Given that
p = 5 and q = 4
on substituting the values we get,
=0.16×52−0.40×5×4+0.25×42
=4−8+4
=0
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:
Steps: 1 Mark
Final expression: 1 Mark
Value: 1 Mark
(0.4p−0.5q)2
=(0.4p−0.5q)×(0.4p−0.5q)
=(0.4p)×(0.4p)−(0.4p×0.5q+0.4p×0.5q)+(0.5q)×(0.5q)
=0.16p2−0.40pq+0.25q2
Given that
p = 5 and q = 4
on substituting the values we get,
=0.16×52−0.40×5×4+0.25×42
=4−8+4
=0
Was this answer helpful ?
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